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53132531221241 is a prime number
BaseRepresentation
bin11000001010010111000011…
…01001100100001011111001
320222010102100110022010222122
430011023201221210023321
523431010410443034431
6305000425312531025
714122461440444303
oct1405134151441371
9228112313263878
1053132531221241
1115a2541a79197a
125b61535250a75
1323854b7668944
14d198b1c26973
1562217455da7b
hex3052e1a642f9

53132531221241 has 2 divisors, whose sum is σ = 53132531221242. Its totient is φ = 53132531221240.

The previous prime is 53132531221183. The next prime is 53132531221291. The reversal of 53132531221241 is 14212213523135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27183491460841 + 25949039760400 = 5213779^2 + 5094020^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53132531221241 is a prime.

It is a super-2 number, since 2×531325312212412 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53132531221291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26566265610620 + 26566265610621.

It is an arithmetic number, because the mean of its divisors is an integer number (26566265610621).

Almost surely, 253132531221241 is an apocalyptic number.

It is an amenable number.

53132531221241 is a deficient number, since it is larger than the sum of its proper divisors (1).

53132531221241 is an equidigital number, since it uses as much as digits as its factorization.

53132531221241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43200, while the sum is 35.

Adding to 53132531221241 its reverse (14212213523135), we get a palindrome (67344744744376).

The spelling of 53132531221241 in words is "fifty-three trillion, one hundred thirty-two billion, five hundred thirty-one million, two hundred twenty-one thousand, two hundred forty-one".