Base | Representation |
---|---|
bin | 1111011101101101001… |
… | …00101100100110000001 |
3 | 1212210111021120110101001 |
4 | 13232312210230212001 |
5 | 32201143034104221 |
6 | 1044032431012001 |
7 | 53250125624062 |
oct | 7566644544601 |
9 | 1783437513331 |
10 | 531344050561 |
11 | 195383956615 |
12 | 86b8a06a001 |
13 | 3b14ab0225c |
14 | 1ba07d78569 |
15 | dc4c74e391 |
hex | 7bb692c981 |
531344050561 has 2 divisors, whose sum is σ = 531344050562. Its totient is φ = 531344050560.
The previous prime is 531344050537. The next prime is 531344050597. The reversal of 531344050561 is 165050443135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 466379726400 + 64964324161 = 682920^2 + 254881^2 .
It is a cyclic number.
It is not a de Polignac number, because 531344050561 - 211 = 531344048513 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 531344050561.
It is not a weakly prime, because it can be changed into another prime (531344053561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265672025280 + 265672025281.
It is an arithmetic number, because the mean of its divisors is an integer number (265672025281).
Almost surely, 2531344050561 is an apocalyptic number.
It is an amenable number.
531344050561 is a deficient number, since it is larger than the sum of its proper divisors (1).
531344050561 is an equidigital number, since it uses as much as digits as its factorization.
531344050561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 531344050561 its reverse (165050443135), we get a palindrome (696394493696).
The spelling of 531344050561 in words is "five hundred thirty-one billion, three hundred forty-four million, fifty thousand, five hundred sixty-one".
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