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53134421300105 = 519801536684221
BaseRepresentation
bin11000001010011010100100…
…10011101001001110001001
320222010121020011211002202112
430011031102103221032021
523431023243323100410
6305001341031512105
714122556331033305
oct1405152223511611
9228117204732675
1053134421300105
1115a261aa681122
125b61982228635
1323857291077c2
14d19a10c6ad05
1562223545c105
hex3053524e9389

53134421300105 has 8 divisors (see below), whose sum is σ = 63764525784264. Its totient is φ = 42505390224000.

The previous prime is 53134421300069. The next prime is 53134421300179. The reversal of 53134421300105 is 50100312443135.

It can be written as a sum of positive squares in 4 ways, for example, as 2162932017481 + 50971489282624 = 1470691^2 + 7139432^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53134421300105 - 244 = 35542235255689 is a prime.

It is a super-2 number, since 2×531344213001052 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 268243106 + ... + 268441115.

It is an arithmetic number, because the mean of its divisors is an integer number (7970565723033).

Almost surely, 253134421300105 is an apocalyptic number.

It is an amenable number.

53134421300105 is a deficient number, since it is larger than the sum of its proper divisors (10630104484159).

53134421300105 is a wasteful number, since it uses less digits than its factorization.

53134421300105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 536704027.

The product of its (nonzero) digits is 21600, while the sum is 32.

The spelling of 53134421300105 in words is "fifty-three trillion, one hundred thirty-four billion, four hundred twenty-one million, three hundred thousand, one hundred five".

Divisors: 1 5 19801 99005 536684221 2683421105 10626884260021 53134421300105