5313511303 has 4 divisors (see below), whose sum is σ = 5318726760. Its totient is φ = 5308295848.

The previous prime is 5313511271. The next prime is 5313511309. The reversal of 5313511303 is 3031153135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5313511303 - 2⁵ = 5313511271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5313511309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2606200 + ... + 2608237.

It is an arithmetic number, because the mean of its divisors is an integer number (1329681690).

Almost surely, 2^5313511303 is an apocalyptic number.

5313511303 is a deficient number, since it is larger than the sum of its proper divisors (5215457).

5313511303 is a wasteful number, since it uses less digits than its factorization.

5313511303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5215456.

The product of its (nonzero) digits is 2025, while the sum is 25.

The square root of 5313511303 is about 72893.8358367839. The cubic root of 5313511303 is about 1744.9937250426.

Adding to 5313511303 its reverse (3031153135), we get a palindrome (8344664438).

The spelling of 5313511303 in words is "five billion, three hundred thirteen million, five hundred eleven thousand, three hundred three".