Base | Representation |
---|---|
bin | 1111011101101110000… |
… | …11001101111001000111 |
3 | 1212210111211121221021122 |
4 | 13232313003031321013 |
5 | 32201202111120041 |
6 | 1044033314304155 |
7 | 53250253625546 |
oct | 7566703157107 |
9 | 1783454557248 |
10 | 531352051271 |
11 | 195388420678 |
12 | 86b9088805b |
13 | 3b14c673ac2 |
14 | 1ba0905c15d |
15 | dc4d2cec4b |
hex | 7bb70cde47 |
531352051271 has 4 divisors (see below), whose sum is σ = 542657414112. Its totient is φ = 520046688432.
The previous prime is 531352051267. The next prime is 531352051273. The reversal of 531352051271 is 172150253135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 531352051271 - 22 = 531352051267 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531352051273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5652681350 + ... + 5652681443.
It is an arithmetic number, because the mean of its divisors is an integer number (135664353528).
Almost surely, 2531352051271 is an apocalyptic number.
531352051271 is a deficient number, since it is larger than the sum of its proper divisors (11305362841).
531352051271 is a wasteful number, since it uses less digits than its factorization.
531352051271 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11305362840.
The product of its (nonzero) digits is 31500, while the sum is 35.
The spelling of 531352051271 in words is "five hundred thirty-one billion, three hundred fifty-two million, fifty-one thousand, two hundred seventy-one".
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