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531352340432 = 24731553292933
BaseRepresentation
bin1111011101101110001…
…00010100011111010000
31212210111212011121221022
413232313010110133100
532201202144343212
61044033324415012
753250256241564
oct7566704243720
91783455147838
10531352340432
111953885a8951
1286b909a7468
133b14c7455c4
141ba090d56a4
15dc4d33a772
hex7bb71147d0

531352340432 has 40 divisors (see below), whose sum is σ = 1044273386184. Its totient is φ = 261867147264.

The previous prime is 531352340423. The next prime is 531352340531. The reversal of 531352340432 is 234043253135.

It can be written as a sum of positive squares in 4 ways, for example, as 53036247616 + 478316092816 = 230296^2 + 691604^2 .

It is a junction number, because it is equal to n+sod(n) for n = 531352340392 and 531352340401.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1667438 + ... + 1960370.

Almost surely, 2531352340432 is an apocalyptic number.

It is an amenable number.

531352340432 is a deficient number, since it is larger than the sum of its proper divisors (512921045752).

531352340432 is a wasteful number, since it uses less digits than its factorization.

531352340432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 294567 (or 294561 counting only the distinct ones).

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 531352340432 its reverse (234043253135), we get a palindrome (765395593567).

The spelling of 531352340432 in words is "five hundred thirty-one billion, three hundred fifty-two million, three hundred forty thousand, four hundred thirty-two".

Divisors: 1 2 4 8 16 73 146 292 584 1168 1553 3106 6212 12424 24848 113369 226738 292933 453476 585866 906952 1171732 1813904 2343464 4686928 21384109 42768218 85536436 171072872 342145744 454924949 909849898 1819699796 3639399592 7278799184 33209521277 66419042554 132838085108 265676170216 531352340432