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531354313417 is a prime number
BaseRepresentation
bin1111011101101110010…
…11110110001011001001
31212210111222212212100211
413232313023312023021
532201203201012132
61044033435001121
753250312066664
oct7566713661311
91783458785324
10531354313417
11195389726214
1286b915991a1
133b14cc86655
141ba0948a6db
15dc4d5ca147
hex7bb72f62c9

531354313417 has 2 divisors, whose sum is σ = 531354313418. Its totient is φ = 531354313416.

The previous prime is 531354313361. The next prime is 531354313459. The reversal of 531354313417 is 714313453135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 419568403081 + 111785910336 = 647741^2 + 334344^2 .

It is a cyclic number.

It is not a de Polignac number, because 531354313417 - 219 = 531353789129 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 531354313417.

It is not a weakly prime, because it can be changed into another prime (531354113417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265677156708 + 265677156709.

It is an arithmetic number, because the mean of its divisors is an integer number (265677156709).

Almost surely, 2531354313417 is an apocalyptic number.

It is an amenable number.

531354313417 is a deficient number, since it is larger than the sum of its proper divisors (1).

531354313417 is an equidigital number, since it uses as much as digits as its factorization.

531354313417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 226800, while the sum is 40.

The spelling of 531354313417 in words is "five hundred thirty-one billion, three hundred fifty-four million, three hundred thirteen thousand, four hundred seventeen".