Base | Representation |
---|---|
bin | 1111011101101110010… |
… | …11110110001101000101 |
3 | 1212210111222212212112102 |
4 | 13232313023312031011 |
5 | 32201203201013131 |
6 | 1044033435001445 |
7 | 53250312100232 |
oct | 7566713661505 |
9 | 1783458785472 |
10 | 531354313541 |
11 | 195389726317 |
12 | 86b91599285 |
13 | 3b14cc8671c |
14 | 1ba0948a789 |
15 | dc4d5ca1cb |
hex | 7bb72f6345 |
531354313541 has 16 divisors (see below), whose sum is σ = 556600699008. Its totient is φ = 506765044800.
The previous prime is 531354313507. The next prime is 531354313561. The reversal of 531354313541 is 145313453135.
It is a cyclic number.
It is not a de Polignac number, because 531354313541 - 226 = 531287204677 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 531354313495 and 531354313504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531354313561) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 130115 + ... + 1039056.
It is an arithmetic number, because the mean of its divisors is an integer number (34787543688).
Almost surely, 2531354313541 is an apocalyptic number.
It is an amenable number.
531354313541 is a deficient number, since it is larger than the sum of its proper divisors (25246385467).
531354313541 is a wasteful number, since it uses less digits than its factorization.
531354313541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1169452.
The product of its digits is 162000, while the sum is 38.
Adding to 531354313541 its reverse (145313453135), we get a palindrome (676667766676).
The spelling of 531354313541 in words is "five hundred thirty-one billion, three hundred fifty-four million, three hundred thirteen thousand, five hundred forty-one".
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