Base | Representation |
---|---|
bin | 1111011101110011110… |
… | …11101001110010101101 |
3 | 1212210122012121022022222 |
4 | 13232321323221302231 |
5 | 32201302000300140 |
6 | 1044042202445125 |
7 | 53251411605224 |
oct | 7567173516255 |
9 | 1783565538288 |
10 | 531400400045 |
11 | 195402743839 |
12 | 86ba4b037a5 |
13 | 3b1596a1748 |
14 | 1ba11645cbb |
15 | dc526805b5 |
hex | 7bb9ee9cad |
531400400045 has 4 divisors (see below), whose sum is σ = 637680480060. Its totient is φ = 425120320032.
The previous prime is 531400400039. The next prime is 531400400051. The reversal of 531400400045 is 540004004135.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (531400400039) and next prime (531400400051).
It can be written as a sum of positive squares in 2 ways, for example, as 77817007849 + 453583392196 = 278957^2 + 673486^2 .
It is a cyclic number.
It is not a de Polignac number, because 531400400045 - 210 = 531400399021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531400399987 and 531400400023.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53140040000 + ... + 53140040009.
It is an arithmetic number, because the mean of its divisors is an integer number (159420120015).
Almost surely, 2531400400045 is an apocalyptic number.
It is an amenable number.
531400400045 is a deficient number, since it is larger than the sum of its proper divisors (106280080015).
531400400045 is a wasteful number, since it uses less digits than its factorization.
531400400045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106280080014.
The product of its (nonzero) digits is 4800, while the sum is 26.
The spelling of 531400400045 in words is "five hundred thirty-one billion, four hundred million, four hundred thousand, forty-five".
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