Base | Representation |
---|---|
bin | 110001011111011001… |
… | …001010100101000000 |
3 | 12002011102100201201122 |
4 | 301133121022211000 |
5 | 1332312322240000 |
6 | 40225011251412 |
7 | 3560600613215 |
oct | 613731124500 |
9 | 162142321648 |
10 | 53140040000 |
11 | 2059a192633 |
12 | a3705a9b68 |
13 | 501b476868 |
14 | 280178bb0c |
15 | 15b039c085 |
hex | c5f64a940 |
53140040000 has 70 divisors (see below), whose sum is σ = 131770127874. Its totient is φ = 21256000000.
The previous prime is 53140039999. The next prime is 53140040069. The reversal of 53140040000 is 4004135.
It can be written as a sum of positive squares in 5 ways, for example, as 33039605824 + 20100434176 = 181768^2 + 141776^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 624251 + ... + 704250.
Almost surely, 253140040000 is an apocalyptic number.
53140040000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53140040000 is an abundant number, since it is smaller than the sum of its proper divisors (78630087874).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53140040000 is an equidigital number, since it uses as much as digits as its factorization.
53140040000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1328533 (or 1328508 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 17.
Adding to 53140040000 its reverse (4004135), we get a palindrome (53144044135).
The spelling of 53140040000 in words is "fifty-three billion, one hundred forty million, forty thousand".
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