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53140149813 = 317713383271
BaseRepresentation
bin110001011111011001…
…100101011000110101
312002011102120022100210
4301133121211120311
51332312334243223
640225013500033
73560601551322
oct613731453065
9162142508323
1053140149813
112059a258093
12a370641619
13501b4b483a
1428017b9b49
1515b03be893
hexc5f665635

53140149813 has 4 divisors (see below), whose sum is σ = 70853533088. Its totient is φ = 35426766540.

The previous prime is 53140149787. The next prime is 53140149833. The reversal of 53140149813 is 31894104135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 53140149813 - 25 = 53140149781 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53140149833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8856691633 + ... + 8856691638.

It is an arithmetic number, because the mean of its divisors is an integer number (17713383272).

Almost surely, 253140149813 is an apocalyptic number.

It is an amenable number.

53140149813 is a deficient number, since it is larger than the sum of its proper divisors (17713383275).

53140149813 is a wasteful number, since it uses less digits than its factorization.

53140149813 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17713383274.

The product of its (nonzero) digits is 51840, while the sum is 39.

The spelling of 53140149813 in words is "fifty-three billion, one hundred forty million, one hundred forty-nine thousand, eight hundred thirteen".

Divisors: 1 3 17713383271 53140149813