Base | Representation |
---|---|
bin | 110001011111011001… |
… | …100101011001001001 |
3 | 12002011102120022101112 |
4 | 301133121211121021 |
5 | 1332312334243313 |
6 | 40225013500105 |
7 | 3560601551351 |
oct | 613731453111 |
9 | 162142508345 |
10 | 53140149833 |
11 | 2059a258101 |
12 | a370641635 |
13 | 501b4b4854 |
14 | 28017b9b61 |
15 | 15b03be8a8 |
hex | c5f665649 |
53140149833 has 2 divisors, whose sum is σ = 53140149834. Its totient is φ = 53140149832.
The previous prime is 53140149787. The next prime is 53140149883. The reversal of 53140149833 is 33894104135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41668240384 + 11471909449 = 204128^2 + 107107^2 .
It is a cyclic number.
It is not a de Polignac number, because 53140149833 - 222 = 53135955529 is a prime.
It is not a weakly prime, because it can be changed into another prime (53140149883) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570074916 + 26570074917.
It is an arithmetic number, because the mean of its divisors is an integer number (26570074917).
Almost surely, 253140149833 is an apocalyptic number.
It is an amenable number.
53140149833 is a deficient number, since it is larger than the sum of its proper divisors (1).
53140149833 is an equidigital number, since it uses as much as digits as its factorization.
53140149833 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 53140149833 in words is "fifty-three billion, one hundred forty million, one hundred forty-nine thousand, eight hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •