Base | Representation |
---|---|
bin | 1111011101110100011… |
… | …10011011111110110011 |
3 | 1212210122112212111000111 |
4 | 13232322032123332303 |
5 | 32201304230333321 |
6 | 1044042500202151 |
7 | 53251501504336 |
oct | 7567216337663 |
9 | 1783575774014 |
10 | 531405324211 |
11 | 1954054a73a3 |
12 | 86ba6699357 |
13 | 3b15a706b58 |
14 | 1ba1216861d |
15 | dc52d045e1 |
hex | 7bba39bfb3 |
531405324211 has 2 divisors, whose sum is σ = 531405324212. Its totient is φ = 531405324210.
The previous prime is 531405324137. The next prime is 531405324239. The reversal of 531405324211 is 112423504135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 531405324211 - 223 = 531396935603 is a prime.
It is not a weakly prime, because it can be changed into another prime (531405324251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265702662105 + 265702662106.
It is an arithmetic number, because the mean of its divisors is an integer number (265702662106).
Almost surely, 2531405324211 is an apocalyptic number.
531405324211 is a deficient number, since it is larger than the sum of its proper divisors (1).
531405324211 is an equidigital number, since it uses as much as digits as its factorization.
531405324211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 531405324211 its reverse (112423504135), we get a palindrome (643828828346).
The spelling of 531405324211 in words is "five hundred thirty-one billion, four hundred five million, three hundred twenty-four thousand, two hundred eleven".
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