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53141400161 is a prime number
BaseRepresentation
bin110001011111011110…
…010110101001100001
312002011111220211111222
4301133132112221201
51332313144301121
640225100344425
73560615306543
oct613736265141
9162144824458
1053141400161
112059aa31533
12a370b45115
13501b8319a5
142801a23693
1515b056a0ab
hexc5f796a61

53141400161 has 2 divisors, whose sum is σ = 53141400162. Its totient is φ = 53141400160.

The previous prime is 53141400127. The next prime is 53141400197. The reversal of 53141400161 is 16100414135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42623667025 + 10517733136 = 206455^2 + 102556^2 .

It is a cyclic number.

It is not a de Polignac number, because 53141400161 - 26 = 53141400097 is a prime.

It is a super-2 number, since 2×531414001612 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53141400161.

It is not a weakly prime, because it can be changed into another prime (53141460161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570700080 + 26570700081.

It is an arithmetic number, because the mean of its divisors is an integer number (26570700081).

Almost surely, 253141400161 is an apocalyptic number.

It is an amenable number.

53141400161 is a deficient number, since it is larger than the sum of its proper divisors (1).

53141400161 is an equidigital number, since it uses as much as digits as its factorization.

53141400161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 53141400161 its reverse (16100414135), we get a palindrome (69241814296).

The spelling of 53141400161 in words is "fifty-three billion, one hundred forty-one million, four hundred thousand, one hundred sixty-one".