Base | Representation |
---|---|
bin | 11000001010100111110001… |
… | …10110110011111111100011 |
3 | 20222011021112020101222212021 |
4 | 30011103320312303333203 |
5 | 23431132303142120134 |
6 | 305004512314042311 |
7 | 14123230112212411 |
oct | 1405237066637743 |
9 | 228137466358767 |
10 | 53141510504419 |
11 | 15a29208313267 |
12 | 5b63220419397 |
13 | 23862b8a4445c |
14 | d1a0c45a82b1 |
15 | 6224ec9e70b4 |
hex | 3054f8db3fe3 |
53141510504419 has 2 divisors, whose sum is σ = 53141510504420. Its totient is φ = 53141510504418.
The previous prime is 53141510504393. The next prime is 53141510504479. The reversal of 53141510504419 is 91440501514135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53141510504419 - 219 = 53141509980131 is a prime.
It is a super-2 number, since 2×531415105044192 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53141510504479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570755252209 + 26570755252210.
It is an arithmetic number, because the mean of its divisors is an integer number (26570755252210).
Almost surely, 253141510504419 is an apocalyptic number.
53141510504419 is a deficient number, since it is larger than the sum of its proper divisors (1).
53141510504419 is an equidigital number, since it uses as much as digits as its factorization.
53141510504419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 43.
The spelling of 53141510504419 in words is "fifty-three trillion, one hundred forty-one billion, five hundred ten million, five hundred four thousand, four hundred nineteen".
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