Base | Representation |
---|---|
bin | 100110101010101001001… |
… | …0111110101001101110011 |
3 | 200211001000200012121201011 |
4 | 1031111102113311031303 |
5 | 1144032044132233042 |
6 | 15145200304251351 |
7 | 1055641142100034 |
oct | 115252227651563 |
9 | 20731020177634 |
10 | 5314256524147 |
11 | 17698442a141a |
12 | 719b31910b57 |
13 | 2c71946b9b7c |
14 | 1452d6098a8b |
15 | 933817d5a17 |
hex | 4d5525f5373 |
5314256524147 has 2 divisors, whose sum is σ = 5314256524148. Its totient is φ = 5314256524146.
The previous prime is 5314256524111. The next prime is 5314256524153. The reversal of 5314256524147 is 7414256524135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5314256524147 - 219 = 5314255999859 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5314256524147.
It is not a weakly prime, because it can be changed into another prime (5314256524177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657128262073 + 2657128262074.
It is an arithmetic number, because the mean of its divisors is an integer number (2657128262074).
Almost surely, 25314256524147 is an apocalyptic number.
5314256524147 is a deficient number, since it is larger than the sum of its proper divisors (1).
5314256524147 is an equidigital number, since it uses as much as digits as its factorization.
5314256524147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4032000, while the sum is 49.
The spelling of 5314256524147 in words is "five trillion, three hundred fourteen billion, two hundred fifty-six million, five hundred twenty-four thousand, one hundred forty-seven".
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