531428070343 has 4 divisors (see below), whose sum is σ = 531429673320. Its totient is φ = 531426467368.

The previous prime is 531428070323. The next prime is 531428070389. The reversal of 531428070343 is 343070824135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 531428070343 - 2²¹ = 531425973191 is a prime.

It is a super-3 number, since 3×531428070343³ (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 531428070296 and 531428070305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531428070323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98905 + ... + 1035682.

It is an arithmetic number, because the mean of its divisors is an integer number (132857418330).

Almost surely, 2^531428070343 is an apocalyptic number.

531428070343 is a deficient number, since it is larger than the sum of its proper divisors (1602977).

531428070343 is a wasteful number, since it uses less digits than its factorization.

531428070343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1602976.

The product of its (nonzero) digits is 241920, while the sum is 40.

Adding to 531428070343 its reverse (343070824135), we get a palindrome (874498894478).

The spelling of 531428070343 in words is "five hundred thirty-one billion, four hundred twenty-eight million, seventy thousand, three hundred forty-three".