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531428070389 is a prime number
BaseRepresentation
bin1111011101110111001…
…01001101001111110101
31212210201010200002220112
413232323211031033311
532201331041223024
61044045031512405
753252166031616
oct7567345151765
91783633602815
10531428070389
11195417322997
1286bb2228705
133b16233c228
141ba151a9c0d
15dc54ce900e
hex7bbb94d3f5

531428070389 has 2 divisors, whose sum is σ = 531428070390. Its totient is φ = 531428070388.

The previous prime is 531428070323. The next prime is 531428070391. The reversal of 531428070389 is 983070824135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 517263024100 + 14165046289 = 719210^2 + 119017^2 .

It is a cyclic number.

It is not a de Polignac number, because 531428070389 - 28 = 531428070133 is a prime.

It is a super-2 number, since 2×5314280703892 (a number of 24 digits) contains 22 as substring.

Together with 531428070391, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531428079389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265714035194 + 265714035195.

It is an arithmetic number, because the mean of its divisors is an integer number (265714035195).

Almost surely, 2531428070389 is an apocalyptic number.

It is an amenable number.

531428070389 is a deficient number, since it is larger than the sum of its proper divisors (1).

531428070389 is an equidigital number, since it uses as much as digits as its factorization.

531428070389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 531428070389 in words is "five hundred thirty-one billion, four hundred twenty-eight million, seventy thousand, three hundred eighty-nine".