Base | Representation |
---|---|
bin | 100110101010101110101… |
… | …1101000011110101111001 |
3 | 200211001111122001100000022 |
4 | 1031111131131003311321 |
5 | 1144032434231203103 |
6 | 15145230545220225 |
7 | 1055645560302623 |
oct | 115253535036571 |
9 | 20731448040008 |
10 | 5314442444153 |
11 | 176992a237917 |
12 | 719b84031675 |
13 | 2c71c40844cb |
14 | 145312a53c13 |
15 | 93392cad138 |
hex | 4d55d743d79 |
5314442444153 has 2 divisors, whose sum is σ = 5314442444154. Its totient is φ = 5314442444152.
The previous prime is 5314442444111. The next prime is 5314442444167. The reversal of 5314442444153 is 3514442444135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5038803793984 + 275638650169 = 2244728^2 + 525013^2 .
It is a cyclic number.
It is not a de Polignac number, because 5314442444153 - 218 = 5314442182009 is a prime.
It is not a weakly prime, because it can be changed into another prime (5314442434153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657221222076 + 2657221222077.
It is an arithmetic number, because the mean of its divisors is an integer number (2657221222077).
Almost surely, 25314442444153 is an apocalyptic number.
It is an amenable number.
5314442444153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5314442444153 is an equidigital number, since it uses as much as digits as its factorization.
5314442444153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1843200, while the sum is 44.
Adding to 5314442444153 its reverse (3514442444135), we get a palindrome (8828884888288).
The spelling of 5314442444153 in words is "five trillion, three hundred fourteen billion, four hundred forty-two million, four hundred forty-four thousand, one hundred fifty-three".
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