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5314442444153 is a prime number
BaseRepresentation
bin100110101010101110101…
…1101000011110101111001
3200211001111122001100000022
41031111131131003311321
51144032434231203103
615145230545220225
71055645560302623
oct115253535036571
920731448040008
105314442444153
11176992a237917
12719b84031675
132c71c40844cb
14145312a53c13
1593392cad138
hex4d55d743d79

5314442444153 has 2 divisors, whose sum is σ = 5314442444154. Its totient is φ = 5314442444152.

The previous prime is 5314442444111. The next prime is 5314442444167. The reversal of 5314442444153 is 3514442444135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5038803793984 + 275638650169 = 2244728^2 + 525013^2 .

It is a cyclic number.

It is not a de Polignac number, because 5314442444153 - 218 = 5314442182009 is a prime.

It is not a weakly prime, because it can be changed into another prime (5314442434153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657221222076 + 2657221222077.

It is an arithmetic number, because the mean of its divisors is an integer number (2657221222077).

Almost surely, 25314442444153 is an apocalyptic number.

It is an amenable number.

5314442444153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5314442444153 is an equidigital number, since it uses as much as digits as its factorization.

5314442444153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1843200, while the sum is 44.

Adding to 5314442444153 its reverse (3514442444135), we get a palindrome (8828884888288).

The spelling of 5314442444153 in words is "five trillion, three hundred fourteen billion, four hundred forty-two million, four hundred forty-four thousand, one hundred fifty-three".