Search a number
-
+
5314520105413 = 11634569664751
BaseRepresentation
bin100110101010110001000…
…0101010100000111000101
3200211001201001011221020021
41031111202011110013011
51144033114121333123
615145242401535141
71055650522355401
oct115254205240705
920731631157207
105314520105413
11176996a060982
12719ba60444b1
132c72071a620c
1414531d0ac101
15933999edc5d
hex4d5621541c5

5314520105413 has 4 divisors (see below), whose sum is σ = 5319089771328. Its totient is φ = 5309950439500.

The previous prime is 5314520105387. The next prime is 5314520105429. The reversal of 5314520105413 is 3145010254135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5314520105413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5314520102413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2284831213 + ... + 2284833538.

It is an arithmetic number, because the mean of its divisors is an integer number (1329772442832).

Almost surely, 25314520105413 is an apocalyptic number.

It is an amenable number.

5314520105413 is a deficient number, since it is larger than the sum of its proper divisors (4569665915).

5314520105413 is a wasteful number, since it uses less digits than its factorization.

5314520105413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4569665914.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 5314520105413 its reverse (3145010254135), we get a palindrome (8459530359548).

The spelling of 5314520105413 in words is "five trillion, three hundred fourteen billion, five hundred twenty million, one hundred five thousand, four hundred thirteen".

Divisors: 1 1163 4569664751 5314520105413