Base | Representation |
---|---|
bin | 1100101011000… |
… | …0000110100001 |
3 | 10201000022020201 |
4 | 3022300012201 |
5 | 102101300423 |
6 | 5135105201 |
7 | 1213524412 |
oct | 312600641 |
9 | 121008221 |
10 | 53150113 |
11 | 28002515 |
12 | 15972201 |
13 | b01c193 |
14 | 70b7809 |
15 | 49ed2ad |
hex | 32b01a1 |
53150113 has 2 divisors, whose sum is σ = 53150114. Its totient is φ = 53150112.
The previous prime is 53150101. The next prime is 53150131. The reversal of 53150113 is 31105135.
Together with next prime (53150131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52085089 + 1065024 = 7217^2 + 1032^2 .
It is a cyclic number.
It is not a de Polignac number, because 53150113 - 25 = 53150081 is a prime.
It is not a weakly prime, because it can be changed into another prime (53150183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575056 + 26575057.
It is an arithmetic number, because the mean of its divisors is an integer number (26575057).
Almost surely, 253150113 is an apocalyptic number.
It is an amenable number.
53150113 is a deficient number, since it is larger than the sum of its proper divisors (1).
53150113 is an equidigital number, since it uses as much as digits as its factorization.
53150113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225, while the sum is 19.
The square root of 53150113 is about 7290.4124026011. The cubic root of 53150113 is about 375.9828746727.
Adding to 53150113 its reverse (31105135), we get a palindrome (84255248).
The spelling of 53150113 in words is "fifty-three million, one hundred fifty thousand, one hundred thirteen".
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