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53150305440000 = 28354110729803
BaseRepresentation
bin11000001010111000001010…
…00100110101000100000000
320222012010020011122000101010
430011130011010311010000
523431303311143040000
6305012525132040520
714123661055014126
oct1405340504650400
9228163204560333
1053150305440000
1115a31a1088256a
125b64a75903140
13238708ab86252
14d1a6ba67d916
15622864bb8d50
hex305705135100

53150305440000 has 180 divisors, whose sum is σ = 176765072832656. Its totient is φ = 14173414656000.

The previous prime is 53150305439863. The next prime is 53150305440031. The reversal of 53150305440000 is 4450305135.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a self number, because there is not a number n which added to its sum of digits gives 53150305440000.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 54884902 + ... + 55844901.

Almost surely, 253150305440000 is an apocalyptic number.

53150305440000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

53150305440000 is an abundant number, since it is smaller than the sum of its proper divisors (123614767392656).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53150305440000 is an equidigital number, since it uses as much as digits as its factorization.

53150305440000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110729842 (or 110729813 counting only the distinct ones).

The product of its (nonzero) digits is 18000, while the sum is 30.

Adding to 53150305440000 its reverse (4450305135), we get a palindrome (53154755745135).

The spelling of 53150305440000 in words is "fifty-three trillion, one hundred fifty billion, three hundred five million, four hundred forty thousand".