Base | Representation |
---|---|
bin | 100110101011000000010… |
… | …1110011110110111001001 |
3 | 200211010000212120100101212 |
4 | 1031112000232132313021 |
5 | 1144040142224320313 |
6 | 15145405405022505 |
7 | 1055666334252641 |
oct | 115260056366711 |
9 | 20733025510355 |
10 | 5315034213833 |
11 | 176a103284173 |
12 | 71a10a254a35 |
13 | 2c728985ab96 |
14 | 14536b497521 |
15 | 933c9c023a8 |
hex | 4d580b9edc9 |
5315034213833 has 2 divisors, whose sum is σ = 5315034213834. Its totient is φ = 5315034213832.
The previous prime is 5315034213829. The next prime is 5315034213857. The reversal of 5315034213833 is 3383124305135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2968463663929 + 2346570549904 = 1722923^2 + 1531852^2 .
It is a cyclic number.
It is not a de Polignac number, because 5315034213833 - 22 = 5315034213829 is a prime.
It is not a weakly prime, because it can be changed into another prime (5315034213233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657517106916 + 2657517106917.
It is an arithmetic number, because the mean of its divisors is an integer number (2657517106917).
Almost surely, 25315034213833 is an apocalyptic number.
It is an amenable number.
5315034213833 is a deficient number, since it is larger than the sum of its proper divisors (1).
5315034213833 is an equidigital number, since it uses as much as digits as its factorization.
5315034213833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 41.
Adding to 5315034213833 its reverse (3383124305135), we get a palindrome (8698158518968).
The spelling of 5315034213833 in words is "five trillion, three hundred fifteen billion, thirty-four million, two hundred thirteen thousand, eight hundred thirty-three".
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