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53150413401 = 3219310821131
BaseRepresentation
bin110001100000000000…
…101111001001011001
312002012010212202100200
4301200000233021121
51332323001212101
640230021452413
73561055026321
oct614000571131
9162163782320
1053150413401
11205a5028298
12a373b71109
135020669377
142802ccc281
1515b124a986
hexc6002f259

53150413401 has 12 divisors (see below), whose sum is σ = 80813494320. Its totient is φ = 33568682040.

The previous prime is 53150413387. The next prime is 53150413409. The reversal of 53150413401 is 10431405135.

It is a happy number.

53150413401 is a `hidden beast` number, since 5 + 315 + 0 + 4 + 1 + 340 + 1 = 666.

It is not a de Polignac number, because 53150413401 - 25 = 53150413369 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53150413409) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 155410395 + ... + 155410736.

It is an arithmetic number, because the mean of its divisors is an integer number (6734457860).

Almost surely, 253150413401 is an apocalyptic number.

It is an amenable number.

53150413401 is a deficient number, since it is larger than the sum of its proper divisors (27663080919).

53150413401 is a wasteful number, since it uses less digits than its factorization.

53150413401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 310821156 (or 310821153 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 53150413401 its reverse (10431405135), we get a palindrome (63581818536).

The spelling of 53150413401 in words is "fifty-three billion, one hundred fifty million, four hundred thirteen thousand, four hundred one".

Divisors: 1 3 9 19 57 171 310821131 932463393 2797390179 5905601489 17716804467 53150413401