Base | Representation |
---|---|
bin | 110001100000000000… |
… | …101111001001100001 |
3 | 12002012010212202100222 |
4 | 301200000233021201 |
5 | 1332323001212114 |
6 | 40230021452425 |
7 | 3561055026332 |
oct | 614000571141 |
9 | 162163782328 |
10 | 53150413409 |
11 | 205a50282a5 |
12 | a373b71115 |
13 | 5020669382 |
14 | 2802ccc289 |
15 | 15b124a98e |
hex | c6002f261 |
53150413409 has 2 divisors, whose sum is σ = 53150413410. Its totient is φ = 53150413408.
The previous prime is 53150413387. The next prime is 53150413411. The reversal of 53150413409 is 90431405135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51732137809 + 1418275600 = 227447^2 + 37660^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53150413409 is a prime.
Together with 53150413411, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (53150413009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575206704 + 26575206705.
It is an arithmetic number, because the mean of its divisors is an integer number (26575206705).
Almost surely, 253150413409 is an apocalyptic number.
It is an amenable number.
53150413409 is a deficient number, since it is larger than the sum of its proper divisors (1).
53150413409 is an equidigital number, since it uses as much as digits as its factorization.
53150413409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 53150413409 in words is "fifty-three billion, one hundred fifty million, four hundred thirteen thousand, four hundred nine".
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