Base | Representation |
---|---|
bin | 11000001010111001101010… |
… | …01101100101110000101011 |
3 | 20222012012022110021111101212 |
4 | 30011130311031211300223 |
5 | 23431311434414333422 |
6 | 305013141221503335 |
7 | 14124020062354601 |
oct | 1405346515456053 |
9 | 228165273244355 |
10 | 53151113042987 |
11 | 15a32295736653 |
12 | 5b65060271b4b |
13 | 238718929b93b |
14 | d1a755a27871 |
15 | 6228b0a439e2 |
hex | 305735365c2b |
53151113042987 has 2 divisors, whose sum is σ = 53151113042988. Its totient is φ = 53151113042986.
The previous prime is 53151113042983. The next prime is 53151113043013. The reversal of 53151113042987 is 78924031115135.
53151113042987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53151113042987 - 22 = 53151113042983 is a prime.
It is not a weakly prime, because it can be changed into another prime (53151113042983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575556521493 + 26575556521494.
It is an arithmetic number, because the mean of its divisors is an integer number (26575556521494).
Almost surely, 253151113042987 is an apocalyptic number.
53151113042987 is a deficient number, since it is larger than the sum of its proper divisors (1).
53151113042987 is an equidigital number, since it uses as much as digits as its factorization.
53151113042987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 907200, while the sum is 50.
The spelling of 53151113042987 in words is "fifty-three trillion, one hundred fifty-one billion, one hundred thirteen million, forty-two thousand, nine hundred eighty-seven".
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