Base | Representation |
---|---|
bin | 1111011110000001001… |
… | …10101110000101001111 |
3 | 1212210221000021010001112 |
4 | 13233000212232011033 |
5 | 32202014130244403 |
6 | 1044101242202235 |
7 | 53254241313044 |
oct | 7570046560517 |
9 | 1783830233045 |
10 | 531512353103 |
11 | 19545a959826 |
12 | 870164b337b |
13 | 3b17693ba64 |
14 | 1ba224691cb |
15 | dc5c3e69d8 |
hex | 7bc09ae14f |
531512353103 has 4 divisors (see below), whose sum is σ = 531924699120. Its totient is φ = 531100007088.
The previous prime is 531512353091. The next prime is 531512353111. The reversal of 531512353103 is 301353215135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 531512353103 - 210 = 531512352079 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 531512353103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531512353003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206171075 + ... + 206173652.
It is an arithmetic number, because the mean of its divisors is an integer number (132981174780).
Almost surely, 2531512353103 is an apocalyptic number.
531512353103 is a deficient number, since it is larger than the sum of its proper divisors (412346017).
531512353103 is a wasteful number, since it uses less digits than its factorization.
531512353103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 412346016.
The product of its (nonzero) digits is 20250, while the sum is 32.
Adding to 531512353103 its reverse (301353215135), we get a palindrome (832865568238).
The spelling of 531512353103 in words is "five hundred thirty-one billion, five hundred twelve million, three hundred fifty-three thousand, one hundred three".
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