Base | Representation |
---|---|
bin | 11000001010111011011101… |
… | …00000111010110000001001 |
3 | 20222012021210110021001102012 |
4 | 30011131232200322300021 |
5 | 23431320422022123032 |
6 | 305013420443145305 |
7 | 14124052645016051 |
oct | 1405355640726011 |
9 | 228167713231365 |
10 | 53152074411017 |
11 | 15a3273937368a |
12 | 5b6528a215235 |
13 | 23872b0500b6a |
14 | d1a80759a561 |
15 | 62291a1436b2 |
hex | 30576e83ac09 |
53152074411017 has 2 divisors, whose sum is σ = 53152074411018. Its totient is φ = 53152074411016.
The previous prime is 53152074410969. The next prime is 53152074411047. The reversal of 53152074411017 is 71011447025135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45740481975241 + 7411592435776 = 6763171^2 + 2722424^2 .
It is a cyclic number.
It is not a de Polignac number, because 53152074411017 - 232 = 53147779443721 is a prime.
It is not a weakly prime, because it can be changed into another prime (53152074411047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26576037205508 + 26576037205509.
It is an arithmetic number, because the mean of its divisors is an integer number (26576037205509).
Almost surely, 253152074411017 is an apocalyptic number.
It is an amenable number.
53152074411017 is a deficient number, since it is larger than the sum of its proper divisors (1).
53152074411017 is an equidigital number, since it uses as much as digits as its factorization.
53152074411017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 117600, while the sum is 41.
The spelling of 53152074411017 in words is "fifty-three trillion, one hundred fifty-two billion, seventy-four million, four hundred eleven thousand, seventeen".
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