Base | Representation |
---|---|
bin | 111100011011011010011101… |
… | …0010000101011000000110011 |
3 | 2120201000002012202102121110021 |
4 | 1320312310322100223000303 |
5 | 1024132120041221200313 |
6 | 5122251000220344311 |
7 | 216650003215020532 |
oct | 17066647220530063 |
9 | 2521002182377407 |
10 | 531533245100083 |
11 | 1443a9a8a8a7a36 |
12 | 4b7468543a5097 |
13 | 19a784a69b1195 |
14 | 95384bc486319 |
15 | 416b5ed50678d |
hex | 1e36d3a42b033 |
531533245100083 has 2 divisors, whose sum is σ = 531533245100084. Its totient is φ = 531533245100082.
The previous prime is 531533245100059. The next prime is 531533245100101. The reversal of 531533245100083 is 380001542335135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 531533245100083 - 25 = 531533245100051 is a prime.
It is not a weakly prime, because it can be changed into another prime (531533245104083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265766622550041 + 265766622550042.
It is an arithmetic number, because the mean of its divisors is an integer number (265766622550042).
Almost surely, 2531533245100083 is an apocalyptic number.
531533245100083 is a deficient number, since it is larger than the sum of its proper divisors (1).
531533245100083 is an equidigital number, since it uses as much as digits as its factorization.
531533245100083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 43.
The spelling of 531533245100083 in words is "five hundred thirty-one trillion, five hundred thirty-three billion, two hundred forty-five million, one hundred thousand, eighty-three".
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