Base | Representation |
---|---|
bin | 11000001011000101011000… |
… | …01101111010010110001011 |
3 | 20222012210112220220212012201 |
4 | 30011202230031322112023 |
5 | 23431412331033131212 |
6 | 305020101411221031 |
7 | 14124332016520003 |
oct | 1405425415722613 |
9 | 228183486825181 |
10 | 53157404583307 |
11 | 15a34a24092a52 |
12 | 5b663172a7777 |
13 | 238794c892a6b |
14 | d1ab91447003 |
15 | 622b2d068b57 |
hex | 3058ac37a58b |
53157404583307 has 2 divisors, whose sum is σ = 53157404583308. Its totient is φ = 53157404583306.
The previous prime is 53157404583293. The next prime is 53157404583313. The reversal of 53157404583307 is 70338540475135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53157404583307 - 215 = 53157404550539 is a prime.
It is not a weakly prime, because it can be changed into another prime (53157404589307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26578702291653 + 26578702291654.
It is an arithmetic number, because the mean of its divisors is an integer number (26578702291654).
Almost surely, 253157404583307 is an apocalyptic number.
53157404583307 is a deficient number, since it is larger than the sum of its proper divisors (1).
53157404583307 is an equidigital number, since it uses as much as digits as its factorization.
53157404583307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21168000, while the sum is 55.
The spelling of 53157404583307 in words is "fifty-three trillion, one hundred fifty-seven billion, four hundred four million, five hundred eighty-three thousand, three hundred seven".
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