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531612265433 is a prime number
BaseRepresentation
bin1111011110001101000…
…11110110101111011001
31212211011222021012000012
413233012203312233121
532202220214443213
61044115211451305
753256563461454
oct7570643665731
91784158235005
10531612265433
111955012a03a7
1287043a56b35
133b191551692
141ba3183649b
15dc660804a8
hex7bc68f6bd9

531612265433 has 2 divisors, whose sum is σ = 531612265434. Its totient is φ = 531612265432.

The previous prime is 531612265421. The next prime is 531612265439. The reversal of 531612265433 is 334562216135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 531422046169 + 190219264 = 728987^2 + 13792^2 .

It is a cyclic number.

It is not a de Polignac number, because 531612265433 - 224 = 531595488217 is a prime.

It is a super-2 number, since 2×5316122654332 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (531612265439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265806132716 + 265806132717.

It is an arithmetic number, because the mean of its divisors is an integer number (265806132717).

Almost surely, 2531612265433 is an apocalyptic number.

It is an amenable number.

531612265433 is a deficient number, since it is larger than the sum of its proper divisors (1).

531612265433 is an equidigital number, since it uses as much as digits as its factorization.

531612265433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 388800, while the sum is 41.

The spelling of 531612265433 in words is "five hundred thirty-one billion, six hundred twelve million, two hundred sixty-five thousand, four hundred thirty-three".