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53161343401 is a prime number
BaseRepresentation
bin110001100000101010…
…011011100110101001
312002012220110001111111
4301200222123212221
51332333300442101
640231052030321
73561246651235
oct614052334651
9162186401444
1053161343401
1120600213151
12a3777623a1
1350229c531a
1428045355c5
1515b21a9251
hexc60a9b9a9

53161343401 has 2 divisors, whose sum is σ = 53161343402. Its totient is φ = 53161343400.

The previous prime is 53161343383. The next prime is 53161343441. The reversal of 53161343401 is 10434316135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50918373801 + 2242969600 = 225651^2 + 47360^2 .

It is a cyclic number.

It is not a de Polignac number, because 53161343401 - 221 = 53159246249 is a prime.

It is a super-2 number, since 2×531613434012 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53161343441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26580671700 + 26580671701.

It is an arithmetic number, because the mean of its divisors is an integer number (26580671701).

Almost surely, 253161343401 is an apocalyptic number.

It is an amenable number.

53161343401 is a deficient number, since it is larger than the sum of its proper divisors (1).

53161343401 is an equidigital number, since it uses as much as digits as its factorization.

53161343401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 53161343401 its reverse (10434316135), we get a palindrome (63595659536).

The spelling of 53161343401 in words is "fifty-three billion, one hundred sixty-one million, three hundred forty-three thousand, four hundred one".