Base | Representation |
---|---|
bin | 11000001011001111010111… |
… | …01010100111000101000011 |
3 | 20222020022101102200101112222 |
4 | 30011213223222213011003 |
5 | 23432004320043212332 |
6 | 305022345303041255 |
7 | 14124611565241466 |
oct | 1405475352470503 |
9 | 228208342611488 |
10 | 53162764038467 |
11 | 15a37224392a36 |
12 | 5b6737214022b |
13 | 23882c50383c5 |
14 | d1b13d1572dd |
15 | 622d43825712 |
hex | 3059ebaa7143 |
53162764038467 has 2 divisors, whose sum is σ = 53162764038468. Its totient is φ = 53162764038466.
The previous prime is 53162764038383. The next prime is 53162764038487. The reversal of 53162764038467 is 76483046726135.
53162764038467 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53162764038467 - 28 = 53162764038211 is a prime.
It is not a weakly prime, because it can be changed into another prime (53162764038487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26581382019233 + 26581382019234.
It is an arithmetic number, because the mean of its divisors is an integer number (26581382019234).
Almost surely, 253162764038467 is an apocalyptic number.
53162764038467 is a deficient number, since it is larger than the sum of its proper divisors (1).
53162764038467 is an equidigital number, since it uses as much as digits as its factorization.
53162764038467 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 121927680, while the sum is 62.
The spelling of 53162764038467 in words is "fifty-three trillion, one hundred sixty-two billion, seven hundred sixty-four million, thirty-eight thousand, four hundred sixty-seven".
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