Base | Representation |
---|---|
bin | 1001111001110111… |
… | …01101110100100001 |
3 | 111201120100111211101 |
4 | 10330323231310201 |
5 | 41342204120213 |
6 | 2235343114401 |
7 | 245523626341 |
oct | 47473556441 |
9 | 14646314741 |
10 | 5317254433 |
11 | 22894a6a57 |
12 | 10448a2a01 |
13 | 6697bb1ca |
14 | 386286d21 |
15 | 211c22bdd |
hex | 13ceedd21 |
5317254433 has 2 divisors, whose sum is σ = 5317254434. Its totient is φ = 5317254432.
The previous prime is 5317254419. The next prime is 5317254457. The reversal of 5317254433 is 3344527135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3679271649 + 1637982784 = 60657^2 + 40472^2 .
It is a cyclic number.
It is not a de Polignac number, because 5317254433 - 25 = 5317254401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5317254392 and 5317254401.
It is not a weakly prime, because it can be changed into another prime (5317254473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2658627216 + 2658627217.
It is an arithmetic number, because the mean of its divisors is an integer number (2658627217).
Almost surely, 25317254433 is an apocalyptic number.
It is an amenable number.
5317254433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5317254433 is an equidigital number, since it uses as much as digits as its factorization.
5317254433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 151200, while the sum is 37.
The square root of 5317254433 is about 72919.5065328887. The cubic root of 5317254433 is about 1745.4033854234.
The spelling of 5317254433 in words is "five billion, three hundred seventeen million, two hundred fifty-four thousand, four hundred thirty-three".
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