Base | Representation |
---|---|
bin | 11111101101001… |
… | …110011000010001 |
3 | 1101001221210221112 |
4 | 133231032120101 |
5 | 2042134332243 |
6 | 124441303105 |
7 | 16116330635 |
oct | 3755163021 |
9 | 1331853845 |
10 | 531949073 |
11 | 2532a9237 |
12 | 12a194a95 |
13 | 86290286 |
14 | 50910dc5 |
15 | 31a79818 |
hex | 1fb4e611 |
531949073 has 2 divisors, whose sum is σ = 531949074. Its totient is φ = 531949072.
The previous prime is 531949063. The next prime is 531949147. The reversal of 531949073 is 370949135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 529782289 + 2166784 = 23017^2 + 1472^2 .
It is a cyclic number.
It is not a de Polignac number, because 531949073 - 26 = 531949009 is a prime.
It is a super-3 number, since 3×5319490733 (a number of 27 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 531949073.
It is not a weakly prime, because it can be changed into another prime (531949013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265974536 + 265974537.
It is an arithmetic number, because the mean of its divisors is an integer number (265974537).
Almost surely, 2531949073 is an apocalyptic number.
It is an amenable number.
531949073 is a deficient number, since it is larger than the sum of its proper divisors (1).
531949073 is an equidigital number, since it uses as much as digits as its factorization.
531949073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 102060, while the sum is 41.
The square root of 531949073 is about 23064.0211801845. The cubic root of 531949073 is about 810.2580456105.
The spelling of 531949073 in words is "five hundred thirty-one million, nine hundred forty-nine thousand, seventy-three".
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