Base | Representation |
---|---|
bin | 100110101101011000001… |
… | …0000110101011110011011 |
3 | 200211121011210000020210221 |
4 | 1031122300100311132123 |
5 | 1144131104414401203 |
6 | 15152011003020511 |
7 | 1056236461643314 |
oct | 115326020653633 |
9 | 20747153006727 |
10 | 5320126715803 |
11 | 1771286921289 |
12 | 71b0ab80a737 |
13 | 2c78bb906463 |
14 | 1456d195760b |
15 | 935c6d2babd |
hex | 4d6b043579b |
5320126715803 has 2 divisors, whose sum is σ = 5320126715804. Its totient is φ = 5320126715802.
The previous prime is 5320126715713. The next prime is 5320126715819. The reversal of 5320126715803 is 3085176210235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5320126715803 - 29 = 5320126715291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5320126715803.
It is not a weakly prime, because it can be changed into another prime (5320126715833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660063357901 + 2660063357902.
It is an arithmetic number, because the mean of its divisors is an integer number (2660063357902).
Almost surely, 25320126715803 is an apocalyptic number.
5320126715803 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320126715803 is an equidigital number, since it uses as much as digits as its factorization.
5320126715803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 5320126715803 in words is "five trillion, three hundred twenty billion, one hundred twenty-six million, seven hundred fifteen thousand, eight hundred three".
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