Base | Representation |
---|---|
bin | 100110101101011000001… |
… | …1111011011000111110111 |
3 | 200211121012001012112122201 |
4 | 1031122300133123013313 |
5 | 1144131111404240043 |
6 | 15152011221005331 |
7 | 1056236536311535 |
oct | 115326037330767 |
9 | 20747161175581 |
10 | 5320130540023 |
11 | 1771288aa34a2 |
12 | 71b0b0b53847 |
13 | 2c78bc645000 |
14 | 1456d2271155 |
15 | 935c7334c4d |
hex | 4d6b07db1f7 |
5320130540023 has 16 divisors (see below), whose sum is σ = 5885895899520. Its totient is φ = 4806402620448.
The previous prime is 5320130539993. The next prime is 5320130540069. The reversal of 5320130540023 is 3200450310235.
It is not a de Polignac number, because 5320130540023 - 25 = 5320130539991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5320130539973 and 5320130540000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320130540323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25657840 + ... + 25864357.
It is an arithmetic number, because the mean of its divisors is an integer number (367868493720).
Almost surely, 25320130540023 is an apocalyptic number.
5320130540023 is a deficient number, since it is larger than the sum of its proper divisors (565765359497).
5320130540023 is an equidigital number, since it uses as much as digits as its factorization.
5320130540023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51522283 (or 51522257 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 5320130540023 its reverse (3200450310235), we get a palindrome (8520580850258).
The spelling of 5320130540023 in words is "five trillion, three hundred twenty billion, one hundred thirty million, five hundred forty thousand, twenty-three".
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