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53201344310201 is a prime number
BaseRepresentation
bin11000001100010111001110…
…01110101010101110111001
320222100222222011021021000002
430012023213032222232321
523433122323120411301
6305052205444122345
714130445623162023
oct1406134716525671
9228328864237002
1053201344310201
1115a516219a812a
125b7293a6963b5
13238bb32c22669
14d1cd5cd59013
15623d5086c16b
hex3062e73aabb9

53201344310201 has 2 divisors, whose sum is σ = 53201344310202. Its totient is φ = 53201344310200.

The previous prime is 53201344310099. The next prime is 53201344310251. The reversal of 53201344310201 is 10201344310235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52274360470201 + 926983840000 = 7230101^2 + 962800^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53201344310201 is a prime.

It is not a weakly prime, because it can be changed into another prime (53201344310251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26600672155100 + 26600672155101.

It is an arithmetic number, because the mean of its divisors is an integer number (26600672155101).

Almost surely, 253201344310201 is an apocalyptic number.

It is an amenable number.

53201344310201 is a deficient number, since it is larger than the sum of its proper divisors (1).

53201344310201 is an equidigital number, since it uses as much as digits as its factorization.

53201344310201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 53201344310201 its reverse (10201344310235), we get a palindrome (63402688620436).

The spelling of 53201344310201 in words is "fifty-three trillion, two hundred one billion, three hundred forty-four million, three hundred ten thousand, two hundred one".