Base | Representation |
---|---|
bin | 110001100011000011… |
… | …011011110111110111 |
3 | 12002022200220210212222 |
4 | 301203003123313313 |
5 | 1332424032440120 |
6 | 40235043432555 |
7 | 3562244612420 |
oct | 614303336767 |
9 | 162280823788 |
10 | 53201452535 |
11 | 206209187a0 |
12 | a38908575b |
13 | 502b0c973a |
14 | 28099b6647 |
15 | 15b597d525 |
hex | c630dbdf7 |
53201452535 has 64 divisors (see below), whose sum is σ = 80317108224. Its totient is φ = 32864832000.
The previous prime is 53201452511. The next prime is 53201452573. The reversal of 53201452535 is 53525410235.
It is not a de Polignac number, because 53201452535 - 26 = 53201452471 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53201452495 and 53201452504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27985085 + ... + 27986985.
It is an arithmetic number, because the mean of its divisors is an integer number (1254954816).
Almost surely, 253201452535 is an apocalyptic number.
53201452535 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53201452535 is a deficient number, since it is larger than the sum of its proper divisors (27115655689).
53201452535 is a wasteful number, since it uses less digits than its factorization.
53201452535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2544.
The product of its (nonzero) digits is 90000, while the sum is 35.
The spelling of 53201452535 in words is "fifty-three billion, two hundred one million, four hundred fifty-two thousand, five hundred thirty-five".
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