Base | Representation |
---|---|
bin | 110001100011000101… |
… | …101011010101010001 |
3 | 12002022202000122221022 |
4 | 301203011223111101 |
5 | 1332424210241040 |
6 | 40235104205225 |
7 | 3562252610522 |
oct | 614305532521 |
9 | 162282018838 |
10 | 53202040145 |
11 | 2062118a221 |
12 | a389309815 |
13 | 502b274037 |
14 | 2809aca849 |
15 | 15b5a476b5 |
hex | c6316b551 |
53202040145 has 4 divisors (see below), whose sum is σ = 63842448180. Its totient is φ = 42561632112.
The previous prime is 53202040093. The next prime is 53202040153. The reversal of 53202040145 is 54104020235.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 39248760769 + 13953279376 = 198113^2 + 118124^2 .
It is a cyclic number.
It is not a de Polignac number, because 53202040145 - 212 = 53202036049 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5320204010 + ... + 5320204019.
It is an arithmetic number, because the mean of its divisors is an integer number (15960612045).
Almost surely, 253202040145 is an apocalyptic number.
It is an amenable number.
53202040145 is a deficient number, since it is larger than the sum of its proper divisors (10640408035).
53202040145 is a wasteful number, since it uses less digits than its factorization.
53202040145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10640408034.
The product of its (nonzero) digits is 4800, while the sum is 26.
The spelling of 53202040145 in words is "fifty-three billion, two hundred two million, forty thousand, one hundred forty-five".
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