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53202040153 is a prime number
BaseRepresentation
bin110001100011000101…
…101011010101011001
312002022202000122221121
4301203011223111121
51332424210241103
640235104205241
73562252610533
oct614305532531
9162282018847
1053202040153
112062118a229
12a389309821
13502b274042
142809aca853
1515b5a476bd
hexc6316b559

53202040153 has 2 divisors, whose sum is σ = 53202040154. Its totient is φ = 53202040152.

The previous prime is 53202040093. The next prime is 53202040211. The reversal of 53202040153 is 35104020235.

53202040153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37408588569 + 15793451584 = 193413^2 + 125672^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53202040153 is a prime.

It is not a weakly prime, because it can be changed into another prime (53202046153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26601020076 + 26601020077.

It is an arithmetic number, because the mean of its divisors is an integer number (26601020077).

Almost surely, 253202040153 is an apocalyptic number.

It is an amenable number.

53202040153 is a deficient number, since it is larger than the sum of its proper divisors (1).

53202040153 is an equidigital number, since it uses as much as digits as its factorization.

53202040153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 25.

Adding to 53202040153 its reverse (35104020235), we get a palindrome (88306060388).

The spelling of 53202040153 in words is "fifty-three billion, two hundred two million, forty thousand, one hundred fifty-three".