Base | Representation |
---|---|
bin | 100110101101100011110… |
… | …1101111100100101111111 |
3 | 200211122012012110111100101 |
4 | 1031123013231330211333 |
5 | 1144132411134114403 |
6 | 15152114021141531 |
7 | 1056252310464031 |
oct | 115330755744577 |
9 | 20748165414311 |
10 | 5320520223103 |
11 | 1771468a62128 |
12 | 71b19b55a8a7 |
13 | 2c79522b3707 |
14 | 14572bd0bc51 |
15 | 935eb65b71d |
hex | 4d6c7b7c97f |
5320520223103 has 4 divisors (see below), whose sum is σ = 5323040604288. Its totient is φ = 5317999841920.
The previous prime is 5320520223091. The next prime is 5320520223107. The reversal of 5320520223103 is 3013220250235.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5320520223103 - 25 = 5320520223071 is a prime.
It is a super-3 number, since 3×53205202231033 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320520223107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1260187426 + ... + 1260191647.
It is an arithmetic number, because the mean of its divisors is an integer number (1330760151072).
Almost surely, 25320520223103 is an apocalyptic number.
5320520223103 is a deficient number, since it is larger than the sum of its proper divisors (2520381185).
5320520223103 is a wasteful number, since it uses less digits than its factorization.
5320520223103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2520381184.
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 5320520223103 its reverse (3013220250235), we get a palindrome (8333740473338).
The spelling of 5320520223103 in words is "five trillion, three hundred twenty billion, five hundred twenty million, two hundred twenty-three thousand, one hundred three".
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