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53209649617801 is a prime number
BaseRepresentation
bin11000001100100110101100…
…10000111001101110001001
320222101210101222011121012021
430012103112100321232021
523433241330300232201
6305100101531444441
714131161502135555
oct1406232620715611
9228353358147167
1053209649617801
1115a550a4044706
125b74477bb6721
13238c8577a1361
14d1d509db8865
15624189a73ea1
hex3064d6439b89

53209649617801 has 2 divisors, whose sum is σ = 53209649617802. Its totient is φ = 53209649617800.

The previous prime is 53209649617717. The next prime is 53209649617819. The reversal of 53209649617801 is 10871694690235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49263272688400 + 3946376929401 = 7018780^2 + 1986549^2 .

It is a cyclic number.

It is not a de Polignac number, because 53209649617801 - 225 = 53209616063369 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53209649617801.

It is not a weakly prime, because it can be changed into another prime (53209649617871) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26604824808900 + 26604824808901.

It is an arithmetic number, because the mean of its divisors is an integer number (26604824808901).

It is a 1-persistent number, because it is pandigital, but 2⋅53209649617801 = 106419299235602 is not.

Almost surely, 253209649617801 is an apocalyptic number.

It is an amenable number.

53209649617801 is a deficient number, since it is larger than the sum of its proper divisors (1).

53209649617801 is an equidigital number, since it uses as much as digits as its factorization.

53209649617801 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19595520, while the sum is 61.

The spelling of 53209649617801 in words is "fifty-three trillion, two hundred nine billion, six hundred forty-nine million, six hundred seventeen thousand, eight hundred one".