Base | Representation |
---|---|
bin | 11000001100101000100001… |
… | …10011000010001111010001 |
3 | 20222101212221102000201001011 |
4 | 30012110100303002033101 |
5 | 23433300333200102423 |
6 | 305100343212010521 |
7 | 14131225025210206 |
oct | 1406242063021721 |
9 | 228355842021034 |
10 | 53210631644113 |
11 | 15a555584015a9 |
12 | 5b746b0a60a41 |
13 | 238c983087508 |
14 | d1d5a05a7cad |
15 | 6241e5da4b0d |
hex | 306510cc23d1 |
53210631644113 has 2 divisors, whose sum is σ = 53210631644114. Its totient is φ = 53210631644112.
The previous prime is 53210631644101. The next prime is 53210631644207. The reversal of 53210631644113 is 31144613601235.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44948818454544 + 8261813189569 = 6704388^2 + 2874337^2 .
It is a cyclic number.
It is not a de Polignac number, because 53210631644113 - 29 = 53210631643601 is a prime.
It is not a weakly prime, because it can be changed into another prime (53210631645113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26605315822056 + 26605315822057.
It is an arithmetic number, because the mean of its divisors is an integer number (26605315822057).
Almost surely, 253210631644113 is an apocalyptic number.
It is an amenable number.
53210631644113 is a deficient number, since it is larger than the sum of its proper divisors (1).
53210631644113 is an equidigital number, since it uses as much as digits as its factorization.
53210631644113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 53210631644113 in words is "fifty-three trillion, two hundred ten billion, six hundred thirty-one million, six hundred forty-four thousand, one hundred thirteen".
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