Base | Representation |
---|---|
bin | 11000001100101001011110… |
… | …01010110101101001000101 |
3 | 20222101221020220211211221012 |
4 | 30012110233022311221011 |
5 | 23433302404121403303 |
6 | 305100505533332005 |
7 | 14131243453315205 |
oct | 1406245712655105 |
9 | 228357226754835 |
10 | 53211141200453 |
11 | 15a55799aa5845 |
12 | 5b74813637005 |
13 | 238ca34807242 |
14 | d1d60c12a405 |
15 | 6242259a95d8 |
hex | 30652f2b5a45 |
53211141200453 has 16 divisors (see below), whose sum is σ = 53617313822976. Its totient is φ = 52806342942720.
The previous prime is 53211141200447. The next prime is 53211141200471. The reversal of 53211141200453 is 35400214111235.
It is a cyclic number.
It is not a de Polignac number, because 53211141200453 - 210 = 53211141199429 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53211141200443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 802100501 + ... + 802166837.
It is an arithmetic number, because the mean of its divisors is an integer number (3351082113936).
Almost surely, 253211141200453 is an apocalyptic number.
It is an amenable number.
53211141200453 is a deficient number, since it is larger than the sum of its proper divisors (406172622523).
53211141200453 is a wasteful number, since it uses less digits than its factorization.
53211141200453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76604.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 53211141200453 its reverse (35400214111235), we get a palindrome (88611355311688).
The spelling of 53211141200453 in words is "fifty-three trillion, two hundred eleven billion, one hundred forty-one million, two hundred thousand, four hundred fifty-three".
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