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5321324214851 is a prime number
BaseRepresentation
bin100110101101111011110…
…1000111011101001000011
3200211201021020022111200112
41031123313220323221003
51144141032444333401
615152325501341535
71056311242344221
oct115336750735103
920751236274615
105321324214851
11177184087a017
1271b3848678ab
132c7a4ca33488
141457a69d5b11
15936470213bb
hex4d6f7a3ba43

5321324214851 has 2 divisors, whose sum is σ = 5321324214852. Its totient is φ = 5321324214850.

The previous prime is 5321324214793. The next prime is 5321324214859. The reversal of 5321324214851 is 1584124231235.

5321324214851 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5321324214851 is a prime.

It is a super-2 number, since 2×53213242148512 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5321324214799 and 5321324214808.

It is not a weakly prime, because it can be changed into another prime (5321324214859) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660662107425 + 2660662107426.

It is an arithmetic number, because the mean of its divisors is an integer number (2660662107426).

Almost surely, 25321324214851 is an apocalyptic number.

5321324214851 is a deficient number, since it is larger than the sum of its proper divisors (1).

5321324214851 is an equidigital number, since it uses as much as digits as its factorization.

5321324214851 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 230400, while the sum is 41.

The spelling of 5321324214851 in words is "five trillion, three hundred twenty-one billion, three hundred twenty-four million, two hundred fourteen thousand, eight hundred fifty-one".