Base | Representation |
---|---|
bin | 100110101110101111000… |
… | …0110101110011111000001 |
3 | 200211212201001002010222111 |
4 | 1031131132012232133001 |
5 | 1144203043041120223 |
6 | 15153212231335321 |
7 | 1056401655342133 |
oct | 115353606563701 |
9 | 20755631063874 |
10 | 5323043301313 |
11 | 1772543199131 |
12 | 71b784521541 |
13 | 2c7c64c333ba |
14 | 1458cb049053 |
15 | 936e7de530d |
hex | 4d75e1ae7c1 |
5323043301313 has 2 divisors, whose sum is σ = 5323043301314. Its totient is φ = 5323043301312.
The previous prime is 5323043301181. The next prime is 5323043301319. The reversal of 5323043301313 is 3131033403235.
5323043301313 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2685511395009 + 2637531906304 = 1638753^2 + 1624048^2 .
It is a cyclic number.
It is not a de Polignac number, because 5323043301313 - 225 = 5323009746881 is a prime.
It is not a weakly prime, because it can be changed into another prime (5323043301319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661521650656 + 2661521650657.
It is an arithmetic number, because the mean of its divisors is an integer number (2661521650657).
Almost surely, 25323043301313 is an apocalyptic number.
It is an amenable number.
5323043301313 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323043301313 is an equidigital number, since it uses as much as digits as its factorization.
5323043301313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 31.
Adding to 5323043301313 its reverse (3131033403235), we get a palindrome (8454076704548).
The spelling of 5323043301313 in words is "five trillion, three hundred twenty-three billion, forty-three million, three hundred one thousand, three hundred thirteen".
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