Base | Representation |
---|---|
bin | 11000001101001101101111… |
… | …10000011111000111001111 |
3 | 20222110210111220210110211112 |
4 | 30012212313300133013033 |
5 | 23434112243313441312 |
6 | 305113450022042235 |
7 | 14132533126654142 |
oct | 1406466760370717 |
9 | 228423456713745 |
10 | 53230612640207 |
11 | 15a62a81130712 |
12 | 5b7854857937b |
13 | 239181883a222 |
14 | d20538144059 |
15 | 6249b5119d22 |
hex | 3069b7c1f1cf |
53230612640207 has 4 divisors (see below), whose sum is σ = 53251495582200. Its totient is φ = 53209729698216.
The previous prime is 53230612640143. The next prime is 53230612640281. The reversal of 53230612640207 is 70204621603235.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53230612640207 - 26 = 53230612640143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53230612640297) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10441467173 + ... + 10441472270.
It is an arithmetic number, because the mean of its divisors is an integer number (13312873895550).
Almost surely, 253230612640207 is an apocalyptic number.
53230612640207 is a deficient number, since it is larger than the sum of its proper divisors (20882941993).
53230612640207 is a wasteful number, since it uses less digits than its factorization.
53230612640207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20882941992.
The product of its (nonzero) digits is 362880, while the sum is 41.
The spelling of 53230612640207 in words is "fifty-three trillion, two hundred thirty billion, six hundred twelve million, six hundred forty thousand, two hundred seven".
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