Base | Representation |
---|---|
bin | 1001111010100100… |
… | …00011110000001001 |
3 | 111201222101002010022 |
4 | 10331102003300021 |
5 | 41400204031213 |
6 | 2240112430225 |
7 | 245624462213 |
oct | 47522036011 |
9 | 14658332108 |
10 | 5323111433 |
11 | 2291837452 |
12 | 1046848375 |
13 | 66aa8c0a3 |
14 | 386d6d5b3 |
15 | 2124cd308 |
hex | 13d483c09 |
5323111433 has 2 divisors, whose sum is σ = 5323111434. Its totient is φ = 5323111432.
The previous prime is 5323111397. The next prime is 5323111439. The reversal of 5323111433 is 3341113235.
5323111433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4718590864 + 604520569 = 68692^2 + 24587^2 .
It is a cyclic number.
It is not a de Polignac number, because 5323111433 - 28 = 5323111177 is a prime.
It is not a weakly prime, because it can be changed into another prime (5323111439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661555716 + 2661555717.
It is an arithmetic number, because the mean of its divisors is an integer number (2661555717).
Almost surely, 25323111433 is an apocalyptic number.
It is an amenable number.
5323111433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323111433 is an equidigital number, since it uses as much as digits as its factorization.
5323111433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3240, while the sum is 26.
The square root of 5323111433 is about 72959.6562012185. The cubic root of 5323111433 is about 1746.0440090474.
Adding to 5323111433 its reverse (3341113235), we get a palindrome (8664224668).
The spelling of 5323111433 in words is "five billion, three hundred twenty-three million, one hundred eleven thousand, four hundred thirty-three".
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