Base | Representation |
---|---|
bin | 110001100100111000… |
… | …011011011001100001 |
3 | 12002101211121221201101 |
4 | 301210320123121201 |
5 | 1333004410341231 |
6 | 40242101034401 |
7 | 3563066365222 |
oct | 614470333141 |
9 | 162354557641 |
10 | 53232121441 |
11 | 206371657a4 |
12 | a3973b5a01 |
13 | 5034577015 |
14 | 280dabb249 |
15 | 15b84da661 |
hex | c64e1b661 |
53232121441 has 2 divisors, whose sum is σ = 53232121442. Its totient is φ = 53232121440.
The previous prime is 53232121433. The next prime is 53232121477. The reversal of 53232121441 is 14412123235.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50014849600 + 3217271841 = 223640^2 + 56721^2 .
It is a cyclic number.
It is not a de Polignac number, because 53232121441 - 23 = 53232121433 is a prime.
It is not a weakly prime, because it can be changed into another prime (53232121141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26616060720 + 26616060721.
It is an arithmetic number, because the mean of its divisors is an integer number (26616060721).
Almost surely, 253232121441 is an apocalyptic number.
It is an amenable number.
53232121441 is a deficient number, since it is larger than the sum of its proper divisors (1).
53232121441 is an equidigital number, since it uses as much as digits as its factorization.
53232121441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5760, while the sum is 28.
Adding to 53232121441 its reverse (14412123235), we get a palindrome (67644244676).
The spelling of 53232121441 in words is "fifty-three billion, two hundred thirty-two million, one hundred twenty-one thousand, four hundred forty-one".
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